Advertisements
Advertisements
प्रश्न
Prove the following identities:
`sinA/(1 - cosA) - cotA = cosecA`
Advertisements
उत्तर
`sinA/(1 - cosA) - cotA`
= `sinA/(1 - cosA) - cosA/sinA`
= `(sin^2A - cosA + cos^2A)/((1 - cosA)sinA)`
= `(1 - cosA)/((1 - cosA)sinA)`
= `1/sinA`
= cosec A
संबंधित प्रश्न
Prove that sin6θ + cos6θ = 1 – 3 sin2θ. cos2θ.
Evaluate
`(sin ^2 63^@ + sin^2 27^@)/(cos^2 17^@+cos^2 73^@)`
Prove the following trigonometric identities.
`cot^2 A cosec^2B - cot^2 B cosec^2 A = cot^2 A - cot^2 B`
If cos θ + cos2 θ = 1, prove that sin12 θ + 3 sin10 θ + 3 sin8 θ + sin6 θ + 2 sin4 θ + 2 sin2 θ − 2 = 1
`(1+ cos theta)(1- costheta )(1+cos^2 theta)=1`
`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`
`(sin theta)/((sec theta + tan theta -1)) + cos theta/((cosec theta + cot theta -1))=1`
Prove that `( sintheta - 2 sin ^3 theta ) = ( 2 cos ^3 theta - cos theta) tan theta`
\[\frac{\sin \theta}{1 + \cos \theta}\]is equal to
Prove that (1 – cos2A) . sec2B + tan2B(1 – sin2A) = sin2A + tan2B
