Advertisements
Advertisements
प्रश्न
Without using trigonometric table , evaluate :
`cosec49°cos41° + (tan31°)/(cot59°)`
Advertisements
उत्तर
`cosec49°cos41° + (tan31°)/(cot59°)`
⇒ `sec(90^circ - 41^circ)cos41^circ + cot(90^circ - 59^circ)/cot56^circ`
⇒ `sec41^circ cos41^circ + cot59^circ/cot59^circ` = 1+ 1 = 2
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities.
`tan θ/(1 - cot θ) + cot θ/(1 - tan θ) = 1 + tan θ + cot θ`
Prove the following identities:
`(1 - sinA)/(1 + sinA) = (secA - tanA)^2`
Prove the following identities:
sec4 A (1 – sin4 A) – 2 tan2 A = 1
If x = a cos θ and y = b cot θ, show that:
`a^2/x^2 - b^2/y^2 = 1`
Write the value of `( 1- sin ^2 theta ) sec^2 theta.`
Write the value of`(tan^2 theta - sec^2 theta)/(cot^2 theta - cosec^2 theta)`
`If sin theta = cos( theta - 45° ),where theta " is acute, find the value of "theta` .
`(sin A)/(1 + cos A) + (1 + cos A)/(sin A)` = 2 cosec A
Prove that `(tan(90 - θ) + cot(90 - θ))/("cosec" θ) = sec θ`.
(1 + sin A)(1 – sin A) is equal to ______.
