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प्रश्न
Without using the trigonometric table, prove that
cos 1°cos 2°cos 3° ....cos 180° = 0.
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उत्तर
LHS = cos 1°cos 2°cos 3° ....cos 180°
= cos 1°cos 2°cos 3° ....cos 89° cos 90° .... cos 180°
= cos 1°cos 2°cos 3° ....cos 89° x 0 x cos 91° .... cos 180°
= 0
= RHS
Hence proved.
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