Question

`(1 + cot^2 theta ) sin^2 theta =1`

Answer 1

LHS= `(1+cot^2 theta)sin^2 theta`

      =`cosec^2 theta   sin^2 theta    (∵ cosec^2 theta - cot^2 theta =1)`

     =`1/(sin ^2theta)xxsin^2 theta`

    =1

Hence, LHS = RHS