हिंदी

(Cos^3 Theta +Sin^3 Theta)/(Cos Theta + Sin Theta) + (Cos ^3 Theta - Sin^3 Theta)/(Cos Theta - Sin Theta) = 2

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प्रश्न

`(cos^3 θ + sin^3 θ)/(cos θ + sin θ) + (cos ^3 θ - sin^3 θ)/(cos θ - sin θ) = 2`

Prove the following:

`(sin^3 θ + cos^3 θ)/(sin θ +cos θ) + (sin^3 θ - cos ^3 θ)/(sin θ - cos θ) = 2`

प्रमेय
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उत्तर

LHS= `(cos^3 θ + sin^3 θ)/(cos θ + sin θ) + (cos ^3 θ - sin^3 θ)/(cos θ - sin θ) `

=` ((cos θ + sin θ)(cos^2 θ - cos θ sin θ + sin^2 θ))/((cos θ + sin θ)) + ((cos θ - sin θ)(cos^2 θ + cos θ sin θ + sin^2 θ))/((cos θ - sin θ))`

= (cos2 θ + sin2 θ − cos θ sin θ) + (cos2 θ + sin2 θ + cos θ sin θ)`

= (1 − cos θ sin θ) + (1 + cos θ sin θ)

= 2

= RHS

Hence, LHS = RHS

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अध्याय 18: Trigonometric identities - Exercise 18A

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
अध्याय 18 Trigonometric identities
Exercise 18A | Q 22. (ii)
आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 13 Trigonometric identities
Exercises 1 | Q 22

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