Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`(1 + cot^2"A")/(1 + tan^2"A")` = ?
विकल्प
tan2A
sec2A
cosec2A
cot2A
Advertisements
उत्तर
cot2A
`(1 + cot^2"A")/(1 + tan^2"A")`
= `("cosec"^2"A")/("sec"^2"A")`
= `(1/("sin"^2"A"))/(1/("cos"^2"A"))`
= `("cos"^2"A")/("sin"^2"A")`
= cot2A
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities.
sin2 A cos2 B − cos2 A sin2 B = sin2 A − sin2 B
Prove the following identities:
`secA/(secA + 1) + secA/(secA - 1) = 2cosec^2A`
Prove the following identities:
`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (1 + cosA)/sinA`
Prove the following identities:
`cosA/(1 + sinA) + tanA = secA`
`(sec^2 theta-1) cot ^2 theta=1`
`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`
`tan theta /((1 - cot theta )) + cot theta /((1 - tan theta)) = (1+ sec theta cosec theta)`
`(1+ tan theta + cot theta )(sintheta - cos theta) = ((sec theta)/ (cosec^2 theta)-( cosec theta)/(sec^2 theta))`
Show that none of the following is an identity:
`sin^2 theta + sin theta =2`
If 5 `tan theta = 4,"write the value of" ((cos theta - sintheta))/(( cos theta + sin theta))`
Write the value of tan10° tan 20° tan 70° tan 80° .
Prove the following identity :
`sin^8θ - cos^8θ = (sin^2θ - cos^2θ)(1 - 2sin^2θcos^2θ)`
Find the value of x , if `cosx = cos60^circ cos30^circ - sin60^circ sin30^circ`
If tan θ = 2, where θ is an acute angle, find the value of cos θ.
Prove that tan2Φ + cot2Φ + 2 = sec2Φ.cosec2Φ.
If x sin3θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ , then show that x2 + y2 = 1.
Prove that `(tan θ + sin θ)/(tan θ - sin θ) = (sec θ + 1)/(sec θ - 1)`
Prove that:
`(cos^3 θ + sin^3 θ)/(cos θ + sin θ) + (cos^3 θ - sin^3 θ)/(cos θ - sin θ) = 2`
tan θ cosec2 θ – tan θ is equal to
If tan θ = `7/24`, then to find value of cos θ complete the activity given below.
Activity:
sec2θ = 1 + `square` ......[Fundamental tri. identity]
sec2θ = 1 + `square^2`
sec2θ = 1 + `square/576`
sec2θ = `square/576`
sec θ = `square`
cos θ = `square` .......`[cos theta = 1/sectheta]`
