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If 5 `Tan Theta = 4,"Write the Value Of" ((Cos Theta - Sintheta))/(( Cos Theta + Sin Theta))`

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If 5 `tan theta = 4,"write the value of" ((cos theta - sintheta))/(( cos theta + sin theta))`

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We have , 

 5 `tan theta = 4`

⇒ `tan theta = 4/5`

 Now ,

   `((cos theta - sintheta))/(( cos theta + sin theta))`

  `=(((cos theta )/(cos theta)- (sin theta )/(cos theta)))/((cos theta/ cos theta+ sin theta/ cos theta)`                             (ЁЭР╖ЁЭСЦЁЭСгЁЭСЦЁЭССЁЭСЦЁЭСЫЁЭСФ ЁЭСЫЁЭСвЁЭСЪЁЭСТЁЭСЯЁЭСОЁЭСбЁЭСЬЁЭСЯ ЁЭСОЁЭСЫЁЭСС ЁЭССЁЭСТЁЭСЫЁЭСЬЁЭСЪЁЭСЦЁЭСЫЁЭСОЁЭСбЁЭСЬЁЭСЯ ЁЭСПЁЭСж cos θ)

   `=((1- tan theta))/((1+ tan theta))`

   `= ((1/1-4/5))/((1/1+4/5))`

    `= ((1/5))/((9/5))`

    `= 1/9`

    

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рдЕрдзреНрдпрд╛рдп 13: Trigonometric identities - Exercises 3

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рдЖрд░.рдПрд╕. рдЕрдЧреНрд░рд╡рд╛рд▓ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 13 Trigonometric identities
Exercises 3 | Q 20

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