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Prove the following identities, where the angles involved are acute angles for which the expressions are defined: tanθ1-cotθ+cotθ1-tanθ=1+secθcosecθ - Mathematics

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प्रश्न

Prove the following identities, where the angles involved are acute angles for which the expressions are defined:

`(tan theta)/(1-cot theta) + (cot theta)/(1-tan theta) = 1+secthetacosectheta`

[Hint: Write the expression in terms of sinθ and cosθ]

योग
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उत्तर

L.H.S

= `(tantheta)/(1-cottheta) + (cottheta)/(1-tantheta) `

= `(sintheta/costheta)/(1-costheta/sintheta) + (costheta/sintheta)/(1-sintheta/costheta)`

= `(sintheta/costheta)/((sintheta-costheta)/(sintheta))+ (costheta/sintheta)/((costheta-sintheta)/costheta)`

= `(sin^2theta)/(costheta(sintheta-costheta)) - (cos^2theta)/(sintheta(sintheta-costheta))`

= `1/(sintheta - costheta)[(sin^2theta)/costheta - cos^2theta/sintheta]`

= `(1/(sintheta-costheta))[(sin^3theta-cos^3theta)/(sinthetacostheta)]`

= `(1/(sintheta-costheta))[((sintheta-costheta)(sin^2theta+cos^2theta+sinthetacostheta))/(sinthetacostheta)]`

= `((1+sinthetacostheta))/((sinthetacostheta))`

= sec θ cosec θ + 1

= R.H.S

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Introduction to Trigonometry - Exercise 8.4 [पृष्ठ १९४]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 8 Introduction to Trigonometry
Exercise 8.4 | Q 5.03 | पृष्ठ १९४

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