हिंदी

If Tan θ = 2, Where θ is an Acute Angle, Find the Value of Cos θ.

Advertisements
Advertisements

प्रश्न

If tan θ = 2, where θ is an acute angle, find the value of cos θ. 

योग
Advertisements

उत्तर

1 + tanθ = sec2 θ  

∴ 1 + (2)2 = sec2 θ 

∴ sec2 θ  = 1 + 4

                = 5

sec θ = `sqrt(5)`

cos θ = `1/(sec theta)`

∴ cos θ = `1/sqrt(5)` 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (October)

APPEARS IN

संबंधित प्रश्न

Prove the following identities:

`(i) cos4^4 A – cos^2 A = sin^4 A – sin^2 A`

`(ii) cot^4 A – 1 = cosec^4 A – 2cosec^2 A`

`(iii) sin^6 A + cos^6 A = 1 – 3sin^2 A cos^2 A.`


Prove the following trigonometric identities.

`(1 + cos A)/sin^2 A = 1/(1 - cos A)`


Prove the following trigonometric identities.

`(cot A - cos A)/(cot A + cos A) = (cosec A - 1)/(cosec A + 1)`


Prove the following trigonometric identities.

`((1 + sin theta - cos theta)/(1 + sin theta + cos theta))^2 = (1 - cos theta)/(1 + cos theta)`


Prove the following identities:

`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`


Prove the following identities:

`(sintheta - 2sin^3theta)/(2cos^3theta - costheta) = tantheta`


Prove the following identities:

`cosecA - cotA = sinA/(1 + cosA)`


`tan theta /((1 - cot theta )) + cot theta /((1 - tan theta)) = (1+ sec theta cosec  theta)`


`sin theta/((cot theta + cosec  theta)) - sin theta /( (cot theta - cosec  theta)) =2`


If `sec theta + tan theta = p,` prove that

(i)`sec theta = 1/2 ( p+1/p)   (ii) tan theta = 1/2 ( p- 1/p) (iii) sin theta = (p^2 -1)/(p^2+1)`


If `cos B = 3/5 and (A + B) =- 90° ,`find the value of sin A.


What is the value of (1 + cot2 θ) sin2 θ?


If sec2 θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.


\[\frac{x^2 - 1}{2x}\] is equal to 


If cos A + cos2 A = 1, then sin2 A + sin4 A =


Prove the following identity :

`(cosecA - sinA)(secA - cosA)(tanA + cotA) = 1`


Prove the following identity : 

`(secθ - tanθ)^2 = (1 - sinθ)/(1 + sinθ)`


Prove that `(tan^2"A")/(tan^2 "A"-1) + (cosec^2"A")/(sec^2"A"-cosec^2"A") = (1)/(1-2 co^2 "A")`


Prove that: `(sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = 2/(sin^2 A - cos^2 A)`.


If cot θ = `40/9`, find the values of cosec θ and sinθ,

We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×