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प्रश्न
If x sin3θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ , then show that x2 + y2 = 1.
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उत्तर
Given: x sin3 θ + y cos3 θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (y cos θ) cos2θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (x sin θ) cos2θ = sin θ. cos θ .....(∵ y cos θ = x sin θ)
⇒ x sin θ ( sin2θ + cos2θ ) = sin θ. cos θ
⇒ x sin θ = sin θ. cos θ
⇒ x = cos θ ....(1)
Again x sin θ = y cos θ
⇒ cos θ sin θ = y cos θ
⇒ y = sin θ .....(2)
Squaring and adding (1) and (2), we get the required result.
Hence proved.
संबंधित प्रश्न
Prove the following trigonometric identities.
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Prove the following identities:
`(cos theta "cosec" theta - sin theta sec theta )/(cos theta + sin theta) = "cosec" theta - sec theta`
Write the value of cos1° cos 2°........cos180° .
Prove that:
`"tan A"/(1 + "tan"^2 "A")^2 + "Cot A"/(1 + "Cot"^2 "A")^2 = "sin A cos A"`.
\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to
Prove the following identity :
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If sin θ + cos θ = a and sec θ + cosec θ = b , then the value of b(a2 – 1) is equal to
`5/(sin^2θ) - 5cot^2θ`, complete the activity given below.
Activity:
`5/(sin^2θ) - 5cot^2θ`
= `square (1/(sin^2θ) - cot^2θ)`
= `5(square - cot^2θ) ...[1/(sin^2θ) = square]`
= 5(1)
= `square`
Prove that `(sin θ)/(sec θ + 1) + (sin θ)/(sec θ - 1) = 2 cot θ`.
