Advertisements
Advertisements
प्रश्न
If x sin3θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ , then show that x2 + y2 = 1.
Advertisements
उत्तर
Given: x sin3 θ + y cos3 θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (y cos θ) cos2θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (x sin θ) cos2θ = sin θ. cos θ .....(∵ y cos θ = x sin θ)
⇒ x sin θ ( sin2θ + cos2θ ) = sin θ. cos θ
⇒ x sin θ = sin θ. cos θ
⇒ x = cos θ ....(1)
Again x sin θ = y cos θ
⇒ cos θ sin θ = y cos θ
⇒ y = sin θ .....(2)
Squaring and adding (1) and (2), we get the required result.
Hence proved.
संबंधित प्रश्न
Prove the following identities:
`(sinA + cosA)/(sinA - cosA) + (sinA - cosA)/(sinA + cosA) = 2/(2sin^2A - 1)`
`cosec theta (1+costheta)(cosectheta - cot theta )=1`
If tanθ `= 3/4` then find the value of secθ.
If sin θ + sin2 θ = 1, then cos2 θ + cos4 θ =
If a cos θ + b sin θ = m and a sin θ − b cos θ = n, then a2 + b2 =
Prove the following identity :
`((1 + tan^2A)cotA)/(cosec^2A) = tanA`
Prove the following identity :
`(tanθ + sinθ)/(tanθ - sinθ) = (secθ + 1)/(secθ - 1)`
Prove the following identity :
`[1/((sec^2θ - cos^2θ)) + 1/((cosec^2θ - sin^2θ))](sin^2θcos^2θ) = (1 - sin^2θcos^2θ)/(2 + sin^2θcos^2θ)`
If sin θ + sin2 θ = 1 show that: cos2 θ + cos4 θ = 1
`(1 + cot^2A)/(1 + tan^2A)` = ?
