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प्रश्न
If x sin3θ + y cos3 θ = sin θ cos θ and x sin θ = y cos θ , then show that x2 + y2 = 1.
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उत्तर
Given: x sin3 θ + y cos3 θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (y cos θ) cos2θ = sin θ. cos θ
⇒ (x sin θ) sin2θ + (x sin θ) cos2θ = sin θ. cos θ .....(∵ y cos θ = x sin θ)
⇒ x sin θ ( sin2θ + cos2θ ) = sin θ. cos θ
⇒ x sin θ = sin θ. cos θ
⇒ x = cos θ ....(1)
Again x sin θ = y cos θ
⇒ cos θ sin θ = y cos θ
⇒ y = sin θ .....(2)
Squaring and adding (1) and (2), we get the required result.
Hence proved.
संबंधित प्रश्न
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`(cosecA - sinA)(secA - cosA) = 1/(tanA + cotA)`
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If sec2 θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.
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Prove the following identity :
`(1 + cosA)/(1 - cosA) = tan^2A/(secA - 1)^2`
Prove the following identity :
`sqrt((1 + sinq)/(1 - sinq)) + sqrt((1- sinq)/(1 + sinq))` = 2secq
Prove that cos2θ . (1 + tan2θ) = 1. Complete the activity given below.
Activity:
L.H.S = `square`
= `cos^2theta xx square .....[1 + tan^2theta = square]`
= `(cos theta xx square)^2`
= 12
= 1
= R.H.S
