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प्रश्न
Write the value of `(1 - cos^2 theta ) cosec^2 theta`.
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उत्तर
`(1- cos^2 theta ) cosec ^2 theta`
= `sin^2 theta xx 1/ (sin^2 theta)`
=1
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L.H.S = `square`
= `cos^2theta xx square .....[1 + tan^2theta = square]`
= `(cos theta xx square)^2`
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