मराठी

If X = a Sec θ and Y = B Tan θ, Then B2x2 − A2y2 = - Mathematics

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प्रश्न

If x = a sec θ and y = b tan θ, then b2x2 − a2y2 =

पर्याय

  •  ab

  • a2 − b2

  •  a2 + b2

  • a2 b2

MCQ
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उत्तर

Given:

`x= a secθ, y=b tanθ`

So,

`b^2x^2-a^2 y^2` 

=` b^2(a secθ)^2-a^2(btan θ)^2` 

= `b^2 a^2 sec^2 θ-a^2 b^2 tan^2θ`

=` b^2 a^2 (sec^2θ-tan^2 θ)`

We know that,`

`sec^2θ-tan^2θ=1`

Therfore, 

`b^2x^2-a^2y^2=a^2b^2`

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पाठ 11: Trigonometric Identities - Exercise 11.4 [पृष्ठ ५७]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 11 Trigonometric Identities
Exercise 11.4 | Q 13 | पृष्ठ ५७

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