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प्रश्न
If `cos theta = 7/25 , "write the value of" ( tan theta + cot theta).`
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उत्तर
`As sin^2 theta = 1 - cos^2 theta`
=` 1- (7/25)^2`
=`1-49/625`
=`(625-49)/625`
⇒ `sin^2 theta = 576/625`
⇒` sintheta = sqrt(576/625)`
⇒`sin theta = 24/25`
Now ,
`tan theta + cot theta `
=`sin theta / cos theta+ cos theta /sin theta`
=`(sin^2 theta + cos^2 theta)/(cos theta sin theta)`
=`1/((7/25xx24/25))`
=`1/((168/625))`
=`625/168`
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