Question

If `cos theta = 7/25 , "write the value of" ( tan theta + cot theta).`

Answer 1

`As sin^2 theta = 1 - cos^2 theta`

    =` 1- (7/25)^2`

    =`1-49/625`

    =`(625-49)/625`

   ⇒ `sin^2 theta = 576/625`

   ⇒` sintheta = sqrt(576/625)`

   ⇒`sin theta = 24/25`

Now , 

`tan theta + cot theta `

  =`sin theta / cos theta+ cos theta /sin theta`

  =`(sin^2 theta + cos^2 theta)/(cos theta sin theta)`

   =`1/((7/25xx24/25))`

   =`1/((168/625))`

   =`625/168`