Question

What is the value of \[6 \tan^2 \theta - \frac{6}{\cos^2 \theta}\]

Answer 1

We have, 

`6 tan^2 θ-6/cos^2 θ= 6 tan^2 θ-6 sec ^2 θ` 

= `-6 (sec^2θ-tan^2 θ)`    ...{`sec ^2 θ-tan ^2 θ-1` }

= -6 × 1

= -6

\[6 \tan^2 \theta - \frac{6}{\cos^2 \theta}\]