मराठी

Show that (cos^2(45^circ + θ) + cos^2(45^circ – θ))/(tan(60^circ + θ) tan(30^circ – θ)) = 1 - Mathematics

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प्रश्न

Show that `(cos^2(45^circ + θ) + cos^2(45^circ - θ))/(tan(60^circ + θ) tan(30^circ - θ)) = 1`

बेरीज
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उत्तर

L.H.S =  `(cos^2(45^circ + θ) + cos^2(45^circ - θ))/(tan(60^circ + θ) xx tan(30^circ - θ))` 

= `(cos^2(45^circ + θ) + [sin{90^circ - (45^circ - θ)}]^2)/(tan(60^circ + θ) xx cot{90^circ - (30^circ - θ)})`   ...[∵ sin (90° – θ) = cos θ and cot (90° – θ) = tan θ]

= `(cos^2(45^circ + θ) + sin^2(45^circ + θ))/(tan(60^circ + θ) xx cot(60^circ + θ))`  ...[∵ sin2θ + cos2θ = 1]

= `1/(tan(60^circ + θ)) xx 1/(tan(60^circ + θ))`  ...`[∵ cot θ = 1/tan θ]`

= 1

= R.H.S

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Introduction To Trigonometry and Its Applications - Exercise 8.3 [पृष्ठ ९५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
पाठ 8 Introduction To Trigonometry and Its Applications
Exercise 8.3 | Q 13 | पृष्ठ ९५
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