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प्रश्न
`5/(sin^2θ) - 5cot^2θ`, complete the activity given below.
Activity:
`5/(sin^2θ) - 5cot^2θ`
= `square (1/(sin^2θ) - cot^2θ)`
= `5(square - cot^2θ) ...[1/(sin^2θ) = square]`
= 5(1)
= `square`
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उत्तर
`5/(sin^2θ) - 5cot^2θ`
= \[\boxed{5}\left(\frac{1}{\text{sin}^2θ} - \text{cot}^2θ\right)\]
= \[5\left(\boxed{\text{cosec}^2θ} - \text{cot}^2θ\right)\] \[...[\frac{1}{\text{sin}^2θ} = \boxed{\text{cosec}^2θ}]\]
= 5(1)
= \[\boxed{5}\]
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