Advertisements
Advertisements
प्रश्न
Prove the following identity :
`cosec^4A - cosec^2A = cot^4A + cot^2A`
Advertisements
उत्तर
LHS = `cosec^4A - cosec^2A`
= `cosec^2A(cosec^2A - 1)`
RHS = `cot^4A + cot^2A`
= `cot^2A(cot^2A + 1)`
= `(cosec^2A - 1)cosec^2A`
Thus , LHS = RHS
APPEARS IN
संबंधित प्रश्न
Prove that: `sqrt((sec theta - 1)/(sec theta + 1)) + sqrt((sec theta + 1)/(sec theta - 1)) = 2 cosec theta`
Find the value of `(cos 38° cosec 52°)/(tan 18° tan 35° tan 60° tan 72° tan 55°)`
If sec θ + tan θ = x, then sec θ =
The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is
Prove the following identity :
`sin^2Acos^2B - cos^2Asin^2B = sin^2A - sin^2B`
Prove the following identity :
`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (cosA + 1)/sinA`
Prove that `sqrt((1 + cos A)/(1 - cos A)) = (tan A + sin A)/(tan A. sin A)`
Prove that: `(1 + cot^2 θ/(1 + cosec θ)) = cosec θ`.
If cot θ + tan θ = x and sec θ – cos θ = y, then prove that `(x^2y)^(2/3) – (xy^2)^(2/3)` = 1
If cosA + cos2A = 1, then sin2A + sin4A = 1.
