मराठी

Sin(45° + θ) – cos(45° – θ) is equal to ______.

Advertisements
Advertisements

प्रश्न

sin(45° + θ) – cos(45° – θ) is equal to ______.

पर्याय

  • 2cosθ

  • 0

  • 2sinθ

  • 1

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

sin(45° + θ) – cos(45° – θ) is equal to 0.

Explanation:

sin(45° + θ) – cos(45° – θ)

= cos[90° – (45° + θ)] – cos(45° – θ)  ...[∵ cos(90° – θ) = sinθ]

= cos(45° – θ) – cos(45° – θ)

= 0

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Introduction To Trigonometry and Its Applications - Exercise 8.1 [पृष्ठ ९१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 10
पाठ 8 Introduction To Trigonometry and Its Applications
Exercise 8.1 | Q 14 | पृष्ठ ९१

संबंधित प्रश्‍न

`Prove the following trigonometric identities.

`(sec A - tan A)^2 = (1 - sin A)/(1 +  sin A)`


Prove the following trigonometric identities.

`(1 + tan^2 A) + (1 + 1/tan^2 A) = 1/(sin^2 A - sin^4 A)`


Prove the following trigonometric identities.

`sin A/(sec A + tan A - 1) + cos A/(cosec A + cot A + 1) = 1`


If x = a sec θ cos ϕ, y = b sec θ sin ϕ and z c tan θ, show that `x^2/a^2 + y^2/b^2 - x^2/c^2 = 1`


Show that : `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec A cosec A`


`(tan^2theta)/((1+ tan^2 theta))+ cot^2 theta/((1+ cot^2 theta))=1`


`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`


`sin theta/((cot theta + cosec  theta)) - sin theta /( (cot theta - cosec  theta)) =2`


If x= a sec `theta + b tan theta and y = a tan theta + b sec theta ,"prove that" (x^2 - y^2 )=(a^2 -b^2)`


If `tan theta = 1/sqrt(5), "write the value of" (( cosec^2 theta - sec^2 theta))/(( cosec^2 theta - sec^2 theta))`.


cos4 A − sin4 A is equal to ______.


Prove the following identity : 

`[1/((sec^2θ - cos^2θ)) + 1/((cosec^2θ - sin^2θ))](sin^2θcos^2θ) = (1 - sin^2θcos^2θ)/(2 + sin^2θcos^2θ)`


If sinA + cosA = m and secA + cosecA = n , prove that n(m2 - 1) = 2m


prove that `1/(1 + cos(90^circ - A)) + 1/(1 - cos(90^circ - A)) = 2cosec^2(90^circ - A)`


Prove that `(sec θ - 1)/(sec θ + 1) = ((sin θ)/(1 + cos θ ))^2`


Prove that: sin4 θ + cos4θ = 1 - 2sin2θ cos2 θ.


Prove that sin2 5° + sin2 10° .......... + sin2 85° + sin2 90° = `9 1/2`.


Prove the following identities.

`(1 - tan^2theta)/(cot^2 theta - 1)` = tan2 θ


If sec θ = `25/7`, find the value of tan θ.

Solution:

1 + tan2 θ = sec2 θ

∴ 1 + tan2 θ = `(25/7)^square`

∴ tan2 θ = `625/49 - square`

= `(625 - 49)/49`

= `square/49`

∴ tan θ = `square/7` ........(by taking square roots)


If `tan θ = 7/24`, then to find value of cos θ complete the activity given below.

Activity:

sec2θ = 1 + `square`   ...[Fundamental tri. identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square/576`

sec2θ = `square/576`

sec θ = `square` 

cos θ = `square   ...`[cos theta = 1/sectheta]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×