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Sin(45° + θ) – cos(45° – θ) is equal to ______. - Mathematics

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प्रश्न

sin(45° + θ) – cos(45° – θ) is equal to ______.

विकल्प

  • 2cosθ

  • 0

  • 2sinθ

  • 1

MCQ
रिक्त स्थान भरें
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उत्तर

sin(45° + θ) – cos(45° – θ) is equal to 0.

Explanation:

sin(45° + θ) – cos(45° – θ)

= cos[90° – (45° + θ)] – cos(45° – θ)  ...[∵ cos(90° – θ) = sinθ]

= cos(45° – θ) – cos(45° – θ)

= 0

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Introduction To Trigonometry and Its Applications - Exercise 8.1 [पृष्ठ ९१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 8 Introduction To Trigonometry and Its Applications
Exercise 8.1 | Q 14 | पृष्ठ ९१

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