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Prove the Following Trigonometric Identities. (Cos Theta)/(Cosec Theta + 1) + (Cos Theta)/(Cosec Theta - 1) = 2 Tan Theta

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प्रश्न

Prove the following trigonometric identities.

`(cos theta)/(cosec theta + 1) + (cos theta)/(cosec theta - 1) = 2 tan theta`

प्रमेय
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उत्तर

In the given question, we need to prove `(cos theta)/(cosec theta + 1) + (cos theta)/(cosec theta - 1) = 2 tan theta`

Using the identity `a^2 - b^2  = (a + b)(a - b)`

`cos theta/((cosec theta + 1)) + cos theta/(cosec theta - 1) = (cos theta(cosec theta - 1)+ cos theta(cosec theta + 1))/(cosec^2 theta - 1)`

`= (cos theta (cosec theta - 1 + cosec theta + 1))/(cosec^2 theta -1)  = (cos theta(2 cosec theta))/cot^2 theta`

`= ((2 cos theta)(1/sin theta))/((cos^2 theta/sin^2 theta))`

`= 2 ((cos theta)/(sin theta))(sin^2 theta/cos^2 theta)`

`= 2 sin theta/cos theta`

`= 2 tan theta`

Hence proved.

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अध्याय 11: Trigonometric Identities - EXERCISE 11.1 [पृष्ठ ११.३५]

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आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 11 Trigonometric Identities
EXERCISE 11.1 | Q 28. | पृष्ठ ११.३५

संबंधित प्रश्न

Prove the following trigonometric identities.

tan2θ cos2θ = 1 − cos2θ


Prove the following identities:

(cosec A + sin A) (cosec A – sin A) = cot2 A + cos2 A


Prove the following identities:

`1 - cos^2A/(1 + sinA) = sinA`


If x cos A + y sin A = m and x sin A – y cos A = n, then prove that : x2 + y2 = m2 + n2


Prove that:

`sqrt(sec^2A + cosec^2A) = tanA + cotA`


`(sec^2 theta-1) cot ^2 theta=1`


Show that none of the following is an identity:

`tan^2 theta + sin theta = cos^2 theta`


Eliminate θ, if
x = 3 cosec θ + 4 cot θ
y = 4 cosec θ – 3 cot θ


If x = a cos θ and y = b sin θ, then b2x2 + a2y2 =


Given `cos38^circ sec(90^circ - 2A) = 1` , Find the value of <A


Prove that sin4θ - cos4θ = sin2θ - cos2θ
= 2sin2θ - 1
= 1 - 2 cos2θ


Prove that: 2(sin6θ + cos6θ) - 3 ( sin4θ + cos4θ) + 1 = 0.


Prove the following identities.

cot θ + tan θ = sec θ cosec θ


If `tan θ = 9/40`, complete the activity to find the value of sec θ.

Activity:

sec2θ = 1 + `square`   ...[Fundamental trigonometric identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square` 

sec θ = `square` 


If cosec A – sin A = p and sec A – cos A = q, then prove that `(p^2q)^(2/3) + (pq^2)^(2/3) = 1`.


sin(45° + θ) – cos(45° – θ) is equal to ______.


If sin θ + cos θ = p and sec θ + cosec θ = q, then prove that q(p2 – 1) = 2p.


If cot θ = `40/9`, find the values of cosec θ and sinθ,

We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


Find the value of sin2θ  + cos2θ

Solution:

In Δ ABC, ∠ABC = 90°, ∠C = θ°

AB2 + BC2 = `square`   .....(Pythagoras theorem)

Divide both sides by AC2

`"AB"^2/"AC"^2 + "BC"^2/"AC"^2 = "AC"^2/"AC"^2`

∴ `("AB"^2/"AC"^2) + ("BC"^2/"AC"^2) = 1`

But `"AB"/"AC" = square and "BC"/"AC" = square`

∴ `sin^2 theta  + cos^2 theta = square` 


Prove the following trigonometry identity:

(sin θ + cos θ)(cosec θ – sec θ) = cosec θ ⋅ sec θ – 2 tan θ


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