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प्रश्न
Choose the correct alternative:
Which is not correct formula?
विकल्प
1 + tan2θ = sec2θ
1 + sec2θ = tan2θ
cosec2θ − cot2θ = 1
sin2θ + cos2θ = 1
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उत्तर
1 + sec2θ = tan2θ
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संबंधित प्रश्न
Prove the following trigonometric identities
`cos theta/(1 - sin theta) = (1 + sin theta)/cos theta`
Prove the following trigonometric identities.
(sec A − cosec A) (1 + tan A + cot A) = tan A sec A − cot A cosec A
Prove the following identities:
`sinA/(1 + cosA) = cosec A - cot A`
Prove that:
`(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB) = 0`
If x cos A + y sin A = m and x sin A – y cos A = n, then prove that : x2 + y2 = m2 + n2
If x = a cos θ and y = b cot θ, show that:
`a^2/x^2 - b^2/y^2 = 1`
`(1-cos^2theta) sec^2 theta = tan^2 theta`
`sin^2 theta + 1/((1+tan^2 theta))=1`
`(sin theta+1-cos theta)/(cos theta-1+sin theta) = (1+ sin theta)/(cos theta)`
If sec2 θ (1 + sin θ) (1 − sin θ) = k, then find the value of k.
If 5x = sec θ and \[\frac{5}{x} = \tan \theta\]find the value of \[5\left( x^2 - \frac{1}{x^2} \right)\]
If sinA + cosA = `sqrt(2)` , prove that sinAcosA = `1/2`
Prove that `(sin θ tan θ)/(1 - cos θ) = 1 + sec θ.`
Prove that: `(sec θ - tan θ)/(sec θ + tan θ ) = 1 - 2 sec θ.tan θ + 2 tan^2θ`
Prove that `(sin θ. cos (90° - θ) cos θ)/sin( 90° - θ) + (cos θ sin (90° - θ) sin θ)/(cos(90° - θ)) = 1`.
Prove that: `1/(sec θ - tan θ) = sec θ + tan θ`.
Prove that: `(sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = 2/(sin^2 A - cos^2 A)`.
If `cos theta/(1 + sin theta) = 1/"a"`, then prove that `("a"^2 - 1)/("a"^2 + 1)` = sin θ
The value of sin2θ + `1/(1 + tan^2 theta)` is equal to
Choose the correct alternative:
sec 60° = ?
