हिंदी

`(Sin Theta+1-cos Theta)/(Cos Theta-1+Sin Theta) = (1+ Sin Theta)/(Cos Theta)`

Advertisements
Advertisements

प्रश्न

`(sin theta+1-cos theta)/(cos theta-1+sin theta) = (1+ sin theta)/(cos theta)`

Advertisements

उत्तर

LHS= `(sin theta+1cos theta)/(cos theta-1+sin theta) `

      =`((sin theta+1-cos theta)(sin theta+cos theta+1))/((cos theta -1 + sin theta)(sin theta + cos theta +1))`

      =`((sin theta + 1 )^2 - cos^2 theta)/((sin theta + cos theta )^2 -1^2)`

       =`(sin^2 theta +1+2 sin theta - cos^2 theta)/(sin^2 + cos^2 theta+2 sin theta  cos theta -1)`

      =`(sin^2 theta + sin^2 theta + cos^2 theta +2sin theta - cos^2 theta)/(2 sin theta   cos theta)`

      =`(2 sin ^2 theta + 2 sin theta)/(2 sin theta cos theta)`

      =`(2 sin theta (1+ sin theta))/(2 sin theta cos theta)`

      =`(1+sin theta)/cos theta`

      = RHS

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Trigonometric identities - Exercises 1

APPEARS IN

आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 13 Trigonometric identities
Exercises 1 | Q 27.2
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×