Advertisements
Advertisements
प्रश्न
Prove that sin2 θ + cos4 θ = cos2 θ + sin4 θ.
Advertisements
उत्तर
L.H.S. = sin2 θ + cos4 θ
= 1 - cos2 θ + cos4 θ
= 1 - cos2 θ (1 - cos2 θ)
= 1 - (1 - sin2 θ) sin2 θ
= 1 - sin2 θ + sin4 θ
= cos2 θ + sin4 θ
= R.H.S.
Hence proved.
संबंधित प्रश्न
`(1+tan^2A)/(1+cot^2A)` = ______.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
`(sintheta - 2sin^3theta)/(2costheta - costheta) =tan theta`
Prove the following trigonometric identities
cosec6θ = cot6θ + 3 cot2θ cosec2θ + 1
Prove the following trigonometric identities
tan2 A + cot2 A = sec2 A cosec2 A − 2
Prove that:
(cosec A – sin A) (sec A – cos A) sec2 A = tan A

From the figure find the value of sinθ.
If cosec θ − cot θ = α, write the value of cosec θ + cot α.
If sec θ + tan θ = x, then sec θ =
The value of sin ( \[{45}^° + \theta) - \cos ( {45}^°- \theta)\] is equal to
If 2sin2θ – cos2θ = 2, then find the value of θ.
