Advertisements
Advertisements
प्रश्न
Prove that sin2 θ + cos4 θ = cos2 θ + sin4 θ.
Advertisements
उत्तर
L.H.S. = sin2 θ + cos4 θ
= 1 - cos2 θ + cos4 θ
= 1 - cos2 θ (1 - cos2 θ)
= 1 - (1 - sin2 θ) sin2 θ
= 1 - sin2 θ + sin4 θ
= cos2 θ + sin4 θ
= R.H.S.
Hence proved.
संबंधित प्रश्न
If `sec alpha=2/sqrt3` , then find the value of `(1-cosecalpha)/(1+cosecalpha)` where α is in IV quadrant.
Prove the following identities:
`((1 + tan^2A)cotA)/(cosec^2A) = tan A`
`(sin theta+1-cos theta)/(cos theta-1+sin theta) = (1+ sin theta)/(cos theta)`
If `(cosec theta - sin theta )= a^3 and (sec theta - cos theta ) = b^3 , " prove that " a^2 b^2 ( a^2+ b^2 ) =1`
If cosec θ − cot θ = α, write the value of cosec θ + cot α.
cos4 A − sin4 A is equal to ______.
2 (sin6 θ + cos6 θ) − 3 (sin4 θ + cos4 θ) is equal to
Prove that:
`(cos^3 θ + sin^3 θ)/(cos θ + sin θ) + (cos^3 θ - sin^3 θ)/(cos θ - sin θ) = 2`
Prove that `(tan(90 - θ) + cot(90 - θ))/("cosec" θ) = sec θ`.
The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.
