Question

`(1-cos^2theta) sec^2 theta = tan^2 theta`

Answer 1

LHS = `(1-cos^2 theta)sec^2 theta`

       =`sin^2 theta xx sec^2 theta   (∵ sin^2 theta + cos^2 theta = 1)`   

    = `sin^2 theta xx 1/(cos^2 theta)`

    =`(sin^2 theta)/(cos^2 theta)`

    =`tan^2 theta`

   =RHS