Advertisements
Advertisements
प्रश्न
Prove that: `cos^2 A + 1/(1 + cot^2 A) = 1`.
Advertisements
उत्तर
LHS = `cos^2 A + 1/(cosec^2 A)`
= cos2 A + sin2 A
= 1
= RHS
Hence proved.
संबंधित प्रश्न
Prove the following identities:
(1 + cot A – cosec A)(1 + tan A + sec A) = 2
Prove the following identities:
`(costhetacottheta)/(1 + sintheta) = cosectheta - 1`
Write the value of ` cosec^2 (90°- theta ) - tan^2 theta`
(cosec θ − sin θ) (sec θ − cos θ) (tan θ + cot θ) is equal to
Prove the following identity :
`(tanθ + 1/cosθ)^2 + (tanθ - 1/cosθ)^2 = 2((1 + sin^2θ)/(1 - sin^2θ))`
Prove that `(sin (90° - θ))/cos θ + (tan (90° - θ))/cot θ + (cosec (90° - θ))/sec θ = 3`.
If cosθ + sinθ = `sqrt2` cosθ, show that cosθ - sinθ = `sqrt2` sinθ.
Choose the correct alternative:
sec 60° = ?
Choose the correct alternative:
tan (90 – θ) = ?
Prove that `(1 + tan^2 A)/(1 + cot^2 A)` = sec2 A – 1
