Advertisements
Advertisements
प्रश्न
Without using trigonometric identity , show that :
`sin(50^circ + θ) - cos(40^circ - θ) = 0`
Advertisements
उत्तर
`sin(50^circ + θ) - cos(40^circ - θ) = 0`
`sin(50^circ + θ) = cos[90^circ - (50^circ + θ)] = cos(40^circ - θ)`
`sin(50^circ + θ) - cos(40^circ - θ)`
= `cos(40^circ - θ) - cos(40^circ - θ)`
= 0
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identity.
`cos^2 A + 1/(1 + cot^2 A) = 1`
Prove the following trigonometric identities.
`tan^2 theta - sin^2 theta tan^2 theta sin^2 theta`
`sqrt((1-cos theta)/(1+cos theta)) = (cosec theta - cot theta)`
If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2?
If cosec2 θ (1 + cos θ) (1 − cos θ) = λ, then find the value of λ.
cos4 A − sin4 A is equal to ______.
Prove the following identity :
`cosecA + cotA = 1/(cosecA - cotA)`
Without using trigonometric table, prove that
`cos^2 26° + cos 64° sin 26° + (tan 36°)/(cot 54°) = 2`
Prove that : `tan"A"/(1 - cot"A") + cot"A"/(1 - tan"A") = sec"A".cosec"A" + 1`.
If tan θ + cot θ = 2, then tan2θ + cot2θ = ?
