English
Maharashtra State BoardSSC (English Medium) 10th Standard

Choose the correct alternative: Which is not correct formula? - Geometry Mathematics 2

Advertisements
Advertisements

Question

Choose the correct alternative:

Which is not correct formula?

Options

  • 1 + tan2θ = sec2θ

  • 1 + sec2θ = tan2θ

  • cosec2θ − cot2θ = 1

  • sin2θ + cos2θ = 1

MCQ
Advertisements

Solution

1 + sec2θ = tan2θ

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Trigonometry - Q.1 (A)

APPEARS IN

RELATED QUESTIONS

If (secA + tanA)(secB + tanB)(secC + tanC) = (secA – tanA)(secB – tanB)(secC – tanC) prove that each of the side is equal to ±1. We have,


(secA + tanA) (1 − sinA) = ______.


Prove the following trigonometric identities.

`sin theta/(1 - cos theta) =  cosec theta + cot theta`


Prove the following identities:

`cot^2A/(cosecA + 1)^2 = (1 - sinA)/(1 + sinA)`


`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

 


Prove that secθ + tanθ =`(costheta)/(1-sintheta)`.


Prove the following identity : 

`sin^4A + cos^4A = 1 - 2sin^2Acos^2A`


Without using trigonometric table , evaluate : 

`(sin49^circ/sin41^circ)^2 + (cos41^circ/sin49^circ)^2`


Find the value of `θ(0^circ < θ < 90^circ)` if : 

`cos 63^circ sec(90^circ - θ) = 1`


Find A if tan 2A = cot (A-24°).


Prove that cot θ. tan (90° - θ) - sec (90° - θ). cosec θ + 1 = 0.


Prove that sin( 90° - θ ) sin θ cot θ = cos2θ.


Without using the trigonometric table, prove that
tan 10° tan 15° tan 75° tan 80° = 1


Prove the following identities.

`sqrt((1 + sin theta)/(1 - sin theta)` = sec θ + tan θ


Choose the correct alternative:

1 + cot2θ = ? 


Choose the correct alternative:

cot θ . tan θ = ?


If tan θ = `9/40`, complete the activity to find the value of sec θ.

Activity:

sec2θ = 1 + `square`     ......[Fundamental trigonometric identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square` 

sec θ = `square` 


tan2θ – sin2θ = tan2θ × sin2θ. For proof of this complete the activity given below.

Activity:

L.H.S = `square`

= `square (1 - (sin^2theta)/(tan^2theta))`

= `tan^2theta (1 - square/((sin^2theta)/(cos^2theta)))`

= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/square)`

= `tan^2theta (1 - square)`

= `tan^2theta xx square`    .....[1 – cos2θ = sin2θ]

= R.H.S


Prove the following:

`tanA/(1 + sec A) - tanA/(1 - sec A)` = 2cosec A


Statement 1: sin2θ + cos2θ = 1

Statement 2: cosec2θ + cot2θ = 1

Which of the following is valid?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×