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Prove that sec2θ − cos2θ = tan2θ + sin2θ - Geometry Mathematics 2

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प्रश्न

Prove that sec2θ − cos2θ = tan2θ + sin2θ

योग
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उत्तर

L.H.S = sec2θ − cos2θ

= 1 + tan2θ – cos2θ     .......[∵ 1 + tan2θ = sec2θ]

= tan2θ + (1 – cos2θ)

= tan2θ + sin2θ       ......`[(because sin^2theta +cos^2theta = 1),(therefore 1 - cos^2theta = sin^2theta)]`

= R.H.S

∴ sec2θ − cos2θ = tan2θ + sin2θ

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अध्याय 6: Trigonometry - Q.2 (B)

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