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प्रश्न
Choose the correct alternative:
1 + cot2θ = ?
विकल्प
tan2θ
sec2θ
cosec2θ
cos2θ
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उत्तर
1 + cot2θ = cosec2θ
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1 + `square` = cosec2θ
1 + `square` = cosec2θ
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`square/square` = cosec2θ ......[Taking root on the both side]
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and sin θ = `1/("cosec" θ)`
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∴ sin θ = `9/41`
The value is cosec θ = `41/9`, and sin θ = `9/41`
