मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Choose the correct alternative: 1 + cot2θ = ? - Geometry Mathematics 2

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प्रश्न

Choose the correct alternative:

1 + cot2θ = ? 

पर्याय

  • tan2θ

  • sec2θ

  • cosec2θ

  • cos2θ

MCQ
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उत्तर

1 + cot2θ = cosec2θ

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Trigonometry - Q.1 (A)

संबंधित प्रश्‍न

If sinθ + sin2 θ = 1, prove that cos2 θ + cos4 θ = 1


Prove the following trigonometric identities

tan2 A + cot2 A = sec2 A cosec2 A − 2


Prove the following identities:

`sqrt((1 + sinA)/(1 - sinA)) = sec A + tan A`


Prove the following identities:

`sqrt((1 - cosA)/(1 + cosA)) = sinA/(1 + cosA)`


If x cos A + y sin A = m and x sin A – y cos A = n, then prove that : x2 + y2 = m2 + n2


`sqrt((1-cos theta)/(1+cos theta)) = (cosec  theta - cot  theta)`


If `(cot theta ) = m and ( sec theta - cos theta) = n " prove that " (m^2 n)(2/3) - (mn^2)(2/3)=1`


Write the value of `3 cot^2 theta - 3 cosec^2 theta.`


If sec θ + tan θ = x, then sec θ =


Prove the following identity : 

`(1 + cosA)/(1 - cosA) = tan^2A/(secA - 1)^2`


Prove the following identity : 

`sqrt((1 + sinq)/(1 - sinq)) + sqrt((1- sinq)/(1 + sinq))` = 2secq


Prove the following identity : 

`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (cosA + 1)/sinA`


Without using trigonometric table , evaluate : 

`(sin49^circ/sin41^circ)^2 + (cos41^circ/sin49^circ)^2`


Find the value of `θ(0^circ < θ < 90^circ)` if : 

`tan35^circ cot(90^circ - θ) = 1`


Without using a trigonometric table, prove that
`(cos 70°)/(sin 20°) + (cos 59°)/(sin 31°) - 8sin^2 30° = 0`.


Prove that:
`(cos^3 θ + sin^3 θ)/(cos θ + sin θ) + (cos^3 θ - sin^3 θ)/(cos θ - sin θ) = 2`


Prove that `(tan^2 theta - 1)/(tan^2 theta + 1)` = 1 – 2 cos2θ


If tan θ = `9/40`, complete the activity to find the value of sec θ.

Activity:

sec2θ = 1 + `square`     ......[Fundamental trigonometric identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square` 

sec θ = `square` 


Prove that sec2θ − cos2θ = tan2θ + sin2θ


Proved that `(1 + secA)/secA = (sin^2A)/(1 - cos A)`.


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