Advertisements
Advertisements
प्रश्न
Prove that: sin4 θ + cos4θ = 1 - 2sin2θ cos2 θ.
Advertisements
उत्तर
LHS = (sin2θ)2 + (cos2 θ)2 + 2 sin2θ cos2θ - 2 sin2θ cos2θ
= ( sin2θ + cos2θ )2 - 2 sin2θ cos2θ
= 1 - 2 sin2θ cos2θ
= RHS
Hence proved.
संबंधित प्रश्न
Prove the following trigonometric identities.
`1/(sec A + tan A) - 1/cos A = 1/cos A - 1/(sec A - tan A)`
Prove the following identities:
`(cosecA - 1)/(cosecA + 1) = (cosA/(1 + sinA))^2`
Prove the following identity :
`(tanθ + secθ - 1)/(tanθ - secθ + 1) = (1 + sinθ)/(cosθ)`
Find the value of `θ(0^circ < θ < 90^circ)` if :
`tan35^circ cot(90^circ - θ) = 1`
Choose the correct alternative:
1 + tan2 θ = ?
Prove that sin2 θ + cos4 θ = cos2 θ + sin4 θ.
Prove that: `cos^2 A + 1/(1 + cot^2 A) = 1`.
Choose the correct alternative:
cos 45° = ?
The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.
Prove that (sec θ + tan θ) (1 – sin θ) = cos θ
