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प्रश्न
sec θ when expressed in term of cot θ, is equal to ______.
पर्याय
`(1 + cot^2 θ)/cotθ`
`sqrt(1 + cot^2 θ)`
`sqrt(1 + cot^2 θ)/cotθ`
`sqrt(1 - cot^2 θ)/cotθ`
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उत्तर
sec θ when expressed in term of cot θ, is equal to `underlinebb(sqrt(1 + cot^2 θ)/cotθ)`.
Explanation:
As we know that,
sec2 θ = 1 + tan2 θ
and cot θ = `1/tanθ`
`\implies` tan θ = `1/cotθ`
∴ sec2 θ = `1 + (1/cotθ)^2`
= `1 + 1/(cot^2 θ)`
`\implies` sec2 θ = `(cot^2 θ + 1)/(cot^2 θ)`
`\implies` sec θ = `sqrt(1 + cot^2 θ)/cotθ`
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संबंधित प्रश्न
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:
`(1+ secA)/sec A = (sin^2A)/(1-cosA)`
[Hint : Simplify LHS and RHS separately.]
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`(1 + tan^2 theta)/(1 + cot^2 theta) = ((1 - tan theta)/(1 - cot theta))^2 = tan^2 theta`
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`sqrt((1 - cos A)/(1 + cos A)) = cosec A - cot A`
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sinθcotθ + sinθcosecθ = 1 + cosθ
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`cos^4A - sin^4A = 2cos^2A - 1`
Prove the following identity :
`(cosecθ)/(tanθ + cotθ) = cosθ`
Prove that cot θ. tan (90° - θ) - sec (90° - θ). cosec θ + 1 = 0.
Simplify (1 + tan2θ)(1 – sinθ)(1 + sinθ)
