Advertisements
Advertisements
प्रश्न
Prove the following Identities :
`(cosecA)/(cotA+tanA)=cosA`
Advertisements
उत्तर
`(cosecA)/(cotA+tanA)=cosA`
= LHS
= `(cosecA)/(cotA+tanA)`
= `(cosecA)/(cosA/sinA+sinA/cosA)`
=`((cosecA)/(cos^2A+sin^2A))/(sinA.cosA)`
= `(1/sinA)/(1/(sinA.cosA))`
= `(sinA.cosA)/sinA`
= cosA
= RHS
APPEARS IN
संबंधित प्रश्न
Find the value of ` ( sin 50°)/(cos 40°)+ (cosec 40°)/(sec 50°) - 4 cos 50° cosec 40 °`
Write the value of cosec2 (90° − θ) − tan2 θ.
If \[\sin \theta = \frac{1}{3}\] then find the value of 9tan2 θ + 9.
If `x/(a cosθ) = y/(b sinθ) "and" (ax)/cosθ - (by)/sinθ = a^2 - b^2 , "prove that" x^2/a^2 + y^2/b^2 = 1`
Find x , if `cos(2x - 6) = cos^2 30^circ - cos^2 60^circ`
If tan θ = 2, where θ is an acute angle, find the value of cos θ.
If 5x = sec θ and `5/x` = tan θ, then `x^2 - 1/x^2` is equal to
1 + cot2θ = ?
Prove the following:
(sin α + cos α)(tan α + cot α) = sec α + cosec α
Let α, β be such that π < α – β < 3π. If sin α + sin β = `-21/65` and cos α + cos β = `-27/65`, then the value of `cos (α - β)/2` is ______.
