Advertisements
Advertisements
प्रश्न
Write the value of `(1 - cos^2 theta ) cosec^2 theta`.
Advertisements
उत्तर
`(1- cos^2 theta ) cosec ^2 theta`
= `sin^2 theta xx 1/ (sin^2 theta)`
=1
APPEARS IN
संबंधित प्रश्न
If tanθ + sinθ = m and tanθ – sinθ = n, show that `m^2 – n^2 = 4\sqrt{mn}.`
Prove the following trigonometric identities.
`(tan^2 A)/(1 + tan^2 A) + (cot^2 A)/(1 + cot^2 A) = 1`
Prove the following trigonometric identities.
`tan A/(1 + tan^2 A)^2 + cot A/((1 + cot^2 A)) = sin A cos A`
If 4 cos2 A – 3 = 0, show that: cos 3 A = 4 cos3 A – 3 cos A
Prove that:
`(sinA - cosA)(1 + tanA + cotA) = secA/(cosec^2A) - (cosecA)/(sec^2A)`
Prove that:
(sin A + cos A) (sec A + cosec A) = 2 + sec A cosec A
`(1+ cos theta + sin theta)/( 1+ cos theta - sin theta )= (1+ sin theta )/(cos theta)`
Write the value of ` sin^2 theta cos^2 theta (1+ tan^2 theta ) (1+ cot^2 theta).`
If `tan theta = 1/sqrt(5), "write the value of" (( cosec^2 theta - sec^2 theta))/(( cosec^2 theta - sec^2 theta))`.
If 5x = sec ` theta and 5/x = tan theta , " find the value of 5 "( x^2 - 1/( x^2))`
If `sin theta = x , " write the value of cot "theta .`
Prove that `(sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/(secθ - tanθ)`
If \[\cos A = \frac{7}{25}\] find the value of tan A + cot A.
If a cos θ + b sin θ = m and a sin θ − b cos θ = n, then a2 + b2 =
Prove that sin2 θ + cos4 θ = cos2 θ + sin4 θ.
Proved that cosec2(90° - θ) - tan2 θ = cos2(90° - θ) + cos2 θ.
sin2θ + sin2(90 – θ) = ?
To prove cot θ + tan θ = cosec θ × sec θ, complete the activity given below.
Activity:
L.H.S. = `square`
= `square/(sinθ) + (sinθ)/(cosθ)`
= `(cos^2θ + sin^2θ)/square`
= `1/(sinθ.cosθ)` ...`[cos^2θ + sin^2θ = square]`
= `1/(sinθ) xx 1/square`
= `square`
= R.H.S.
Prove that sin6A + cos6A = 1 – 3sin2A . cos2A.
If 2sin2θ – cos2θ = 2, then find the value of θ.
