Question

`(sec^2 theta-1) cot ^2 theta=1`

Answer 1

LHS = `(sec^2 theta -1 ) cot^2 theta`

       =`tan^2theta  xx cot^2 theta       (∵ sec^2 theta - tan^2 theta =1)`

     =`1/(cot^2theta) xx cot^2 theta`

    =1

    =RHS