Advertisements
Advertisements
प्रश्न
Prove the following identities:
`1 - sin^2A/(1 + cosA) = cosA`
Advertisements
उत्तर
`1-sin^2A/(1 + cosA)`
= `(1 + cosA - sin^2A)/(1 + cosA)`
= `(cosA + cos^2A)/(1 + cosA)`
= `(cosA(1 + cosA))/(1 + cosA)`
= cos A
संबंधित प्रश्न
Evaluate sin25° cos65° + cos25° sin65°
Prove the following trigonometric identities
(1 + cot2 A) sin2 A = 1
Prove that:
`tanA/(1 - cotA) + cotA/(1 - tanA) = secA "cosec" A + 1`
`1+((tan^2 theta) cot theta)/(cosec^2 theta) = tan theta`
`(cos theta cosec theta - sin theta sec theta )/(costheta + sin theta) = cosec theta - sec theta`
`If sin theta = cos( theta - 45° ),where theta " is acute, find the value of "theta` .
What is the value of (1 − cos2 θ) cosec2 θ?
Prove the following identity :
`(1 - cos^2θ)sec^2θ = tan^2θ`
Prove that `[(1 + sin theta - cos theta)/(1 + sin theta + cos theta)]^2 = (1 - cos theta)/(1 + cos theta)`
`(cos^2 θ)/(sin^2 θ) - 1/(sin^2 θ)`, in simplified form, is ______.
