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If `Cos Theta = 5/13` Where `Theta` Is an Acute Angle. Find the Value of `Sin Theta` - Geometry Mathematics 2

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प्रश्न

if `cos theta = 5/13` where `theta` is an acute angle. Find the value of `sin theta`

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उत्तर

`cos theta = 5/13`

`sin^2 theta = 1 - cos^2 theta = 1 - 25/169 = 144/169`

`sin theta = +- 12/13` as `theta` is acute, therefore `sintheta` must be positive

`:. sin theta  = 12/13`

 

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2017-2018 (March) Set A

संबंधित प्रश्न

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`secA/(secA + 1) + secA/(secA - 1) = 2cosec^2A`


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`tan^2A - tan^2B = (sin^2A - sin^2B)/(cos^2A * cos^2B)`


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`1/(cosA + sinA - 1) + 1/(cosA + sinA + 1) = cosecA + secA`


If 2 sin A – 1 = 0, show that: sin 3A = 3 sin A – 4 sin3 A


`(sin theta+1-cos theta)/(cos theta-1+sin theta) = (1+ sin theta)/(cos theta)`


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If `secθ = 25/7 ` then find tanθ.


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The value of sin θ+cos θ is always greater than 1 .


prove that `1/(1 + cos(90^circ - A)) + 1/(1 - cos(90^circ - A)) = 2cosec^2(90^circ - A)`


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Choose the correct alternative:

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Activity:

`5/(sin^2theta) - 5cot^2theta`

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∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


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