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Nootan solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई chapter 18 - Trigonometric identities [Latest edition]

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Nootan solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई chapter 18 - Trigonometric identities - Shaalaa.com
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Solutions for Chapter 18: Trigonometric identities

Below listed, you can find solutions for Chapter 18 of CISCE Nootan for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई.


Exercise 18A
Exercise 18A [Pages 423 - 424]

Nootan solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई 18 Trigonometric identities Exercise 18A [Pages 423 - 424]

Exercise 18A | Q 1. | Page 423

Prove the following trigonometric identities.

`"cosec" theta sqrt(1 - cos^2 theta) = 1`

Exercise 18A | Q 2. | Page 423

Prove the following trigonometric identities.

(sec2 θ − 1) (cosec2 θ − 1) = 1

Exercise 18A | Q 3. | Page 423

Prove the following trigonometric identities.

`tan theta + 1/tan theta` = sec θ.cosec θ

Exercise 18A | Q 4. | Page 423

Prove the following:

`1/(tan⁡ theta + cot theta) = sin theta.cos⁡ theta`

Exercise 18A | Q 7. | Page 423

Prove the following:

cot2 θ − cos2 θ = cot2 θ.cos2θ

Exercise 18A | Q 8. | Page 423

Prove the following:

`1/(1 + sinA) - 1/(1 - sinA) = - 2secA tanA`

Exercise 18A | Q 9. | Page 423

Prove the following:

`1/(1 - cosA) - 1/(1 + cosA)` = 2cot A cosec A

Exercise 18A | Q 10. | Page 423

Prove the following trigonometric identities.

`(1 + sin θ)/cos θ+ cos θ/(1 + sin θ) = 2 sec θ`

Exercise 18A | Q 11. | Page 423

Prove the following identities:

`secA/(secA + 1) + secA/(secA - 1) = 2cosec^2A`

Exercise 18A | Q 12. | Page 423

Prove the following:

`1/(sinθ + cosθ) + 1/(sinθ - cosθ) = (2 sinθ)/(2sin^2θ - 1)`

Exercise 18A | Q 13. | Page 424

`sqrt((1 + sin θ)/(1 - sin θ)) = sec θ + tan θ`

Exercise 18A | Q 14. | Page 424

Prove that: `sqrt((1 - cos θ)/(1 + cos θ)) = "cosec" θ - cot θ`.

Exercise 18A | Q 15. | Page 424

Prove that: `(sin θ - 2sin^3 θ)/(2 cos^3 θ - cos θ) = tan θ`.

Exercise 18A | Q 16. | Page 424

Prove the following:

`((1 + sin θ)^2 + ( 1 - sin θ)^2)/(2cos^2θ) = sec^2 θ + tan^2 θ`

Exercise 18A | Q 17. | Page 424

Prove the following:

`sin A/(1 + cot A) - cos A/(1 + tan A) = sin A - cos A`

Exercise 18A | Q 18. | Page 424

`1 + (tan^2 θ)/((1 + sec θ)) = sec θ`

Exercise 18A | Q 19. | Page 424

Prove the following:

`((1 - tan θ)/(1 - cot θ))^2 = tan^2θ`

Exercise 18A | Q 20. (i) | Page 424

Prove that: `(sec θ - tan θ)/(sec θ + tan θ ) = 1 - 2 sec θ.tan θ + 2 tan^2θ`

Exercise 18A | Q 20. (ii) | Page 424

Prove that: 

(sin A + sec A)2 + (cos A + cosec A)2 = (1 + sec A cosec A)2

Exercise 18A | Q 21. | Page 424

Prove the following trigonometric identities.

sec6 θ = tan6 θ + 3 tan2 θ sec2 θ + 1

Exercise 18A | Q 22. (i) | Page 424

Prove the following trigonometric identities.

`tan θ/(1 - cot θ) + cot θ/(1 - tan θ) = 1 + tan θ + cot θ`

Exercise 18A | Q 23. | Page 424

Prove the following trigonometric identities.

`(1 + cos θ + sin θ)/(1 + cos θ - sin θ) = (1 + sin θ)/cos θ`

Exercise 18A | Q 24. (i) | Page 424

Prove that `(tan θ + sin θ)/(tan θ - sin θ) = (sec θ + 1)/(sec θ - 1)`

Exercise 18A | Q 24. (ii) | Page 424

Prove the following:

`(1 + tan θ)/sin θ + (1 + cot θ)/cos θ` = 2(sec θ + cosec θ)

Exercise 18A | Q 25. | Page 424

Prove the following trigonometric identities.

`1/(sec A + tan A) - 1/cos A = 1/cos A - 1/(sec A - tan A)`

Exercise 18A | Q 26. | Page 424

If tan A = n tan B and sin A = m sin B, prove that `cos^2A = (m^2 - 1)/(n^2 - 1)`

Exercise 18A | Q 27. | Page 424

If a cos θ – b sin θ = m and a sin θ + b cos θ = n, prove that: a2 + b2 = m2 + n2

Exercise 18A | Q 28. | Page 424

If sin θ + cos θ = m and sec θ + cosec θ = n, prove that n(m2 – 1) = 2m

Solutions for 18: Trigonometric identities

Exercise 18A
Nootan solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई chapter 18 - Trigonometric identities - Shaalaa.com

Nootan solutions for मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई chapter 18 - Trigonometric identities

Shaalaa.com has the CISCE Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Nootan solutions for Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई CISCE 18 (Trigonometric identities) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई chapter 18 Trigonometric identities are Trigonometric Ratios of Complementary Angles, Application of Trigonometric Tables, Trigonometric Ratios, Relation Among Trigonometric Ratios, Elimination of Trigonometrical Ratios, Trigonometric Identities (Square Relations).

Using Nootan मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई solutions Trigonometric identities exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Nootan Solutions are essential questions that can be asked in the final exam. Maximum CISCE मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई students prefer Nootan Textbook Solutions to score more in exams.

Get the free view of Chapter 18, Trigonometric identities मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई additional questions for Mathematics मैथमैटिक्स [अंग्रेजी] कक्षा १० आईसीएसई CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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