Prove that Cos θ/Sin(90° - θ) + Sin θ/Cos (90° - θ) = 2

Prove that `cos θ/sin(90° - θ) + sin θ/cos (90° - θ) = 2`.

Sum

LHS = `cos θ/sin(90° - θ) + sin θ/cos (90° - θ) `

= `cos θ/cos θ + sin θ/sin θ`

= 1 + 1 = 2

= RHS

Hence proved.

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