Advertisements
Advertisements
Question
Prove that:
`cot^2A/(cosecA - 1) - 1 = cosecA`
Advertisements
Solution
`cot^2A/(cosecA - 1) - 1`
= `(cot^2A - cosecA + 1)/(cosecA - 1)`
= `(-cosecA + cosec^2A)/(cosecA - 1)`
= `(cosecA(cosecA - 1))/(cosecA - 1)`
= cosec A
APPEARS IN
RELATED QUESTIONS
Prove the following trigonometric identities.
`tan theta + 1/tan theta` = sec θ.cosec θ
Prove the following trigonometric identities.
`(cos theta - sin theta + 1)/(cos theta + sin theta - 1) = cosec theta + cot theta`
Prove the following trigonometric identities.
`(1 + cos theta - sin^2 theta)/(sin theta (1 + cos theta)) = cot theta`
Prove the following trigonometric identities.
if x = a cos^3 theta, y = b sin^3 theta` " prove that " `(x/a)^(2/3) + (y/b)^(2/3) = 1`
Prove the following identities:
`(sinA - cosA + 1)/(sinA + cosA - 1) = cosA/(1 - sinA)`
Prove that
`cot^2A-cot^2B=(cos^2A-cos^2B)/(sin^2Asin^2B)=cosec^2A-cosec^2B`
`(sec^2 theta -1)(cosec^2 theta - 1)=1`
The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is
The value of sin2 29° + sin2 61° is
Prove that: `1/(sec θ - tan θ) = sec θ + tan θ`.
