Advertisements
Advertisements
Question
The value of sin2 29° + sin2 61° is
Options
1
0
2 sin2 29°
2 cos2 61°
Advertisements
Solution
The given expression is `sin^29°+sin^2 61°`
`sin^2 29°+sin^2 61°`.
=` sin^2 29°+(sin 61°)^2`
`= sin^2 29°+{sin(90°-29°)}^2`
`=sin^2 29°+(cos 29°)^2`
`= sin^2 29°+cos^2°29°`
`= 1`
APPEARS IN
RELATED QUESTIONS
Prove the following trigonometric identities
(1 + cot2 A) sin2 A = 1
Prove the following trigonometric identities.
`1/(sec A + tan A) - 1/cos A = 1/cos A - 1/(sec A - tan A)`
Prove the following trigonometric identities.
(sec A − cosec A) (1 + tan A + cot A) = tan A sec A − cot A cosec A
Prove the following trigonometric identities.
`tan A/(1 + tan^2 A)^2 + cot A/((1 + cot^2 A)) = sin A cos A`
If 3 sin θ + 5 cos θ = 5, prove that 5 sin θ – 3 cos θ = ± 3.
Prove the following identities:
`sqrt((1 - cosA)/(1 + cosA)) = cosec A - cot A`
`(sec^2 theta -1)(cosec^2 theta - 1)=1`
Show that none of the following is an identity:
(i) `cos^2theta + cos theta =1`
If a cos `theta + b sin theta = m and a sin theta - b cos theta = n , "prove that "( m^2 + n^2 ) = ( a^2 + b^2 )`
If \[\sin \theta = \frac{1}{3}\] then find the value of 2cot2 θ + 2.
The value of \[\sqrt{\frac{1 + \cos \theta}{1 - \cos \theta}}\]
If x = a sec θ and y = b tan θ, then b2x2 − a2y2 =
2 (sin6 θ + cos6 θ) − 3 (sin4 θ + cos4 θ) is equal to
(sec A + tan A) (1 − sin A) = ______.
Prove the following identity :
`(1 + sinA)/(1 - sinA) = (cosecA + 1)/(cosecA - 1)`
Prove the following identity :
`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`
Prove that `(sin^2θ)/(cos θ) + cos θ = sec θ`.
If 4 tanβ = 3, then `(4sinbeta-3cosbeta)/(4sinbeta+3cosbeta)=` ______.
Simplify (1 + tan2θ)(1 – sinθ)(1 + sinθ)
If sin A = `1/2`, then the value of sec A is ______.
