Question

`cot^2 theta - 1/(sin^2 theta ) = -1`a

Answer 1

LHS = `cot^2 theta - 1/ (sin^2 theta)`

       = `(cos^2 theta )/(sin^2 theta) - 1/(sin^2 theta)`

       =`(cos^2 theta -1)/(sin^2 theta)`

      =` (- sin^2 theta )/(sin ^2 theta)`

      =  -1

     = RHS