Advertisements
Advertisements
प्रश्न
`(1+tan^2A)/(1+cot^2A)` = ______.
पर्याय
sec2 A
−1
cot2 A
tan2 A
Advertisements
उत्तर
`(1+tan^2A)/(1+cot^2A)` = tan2 A.
Explanation:
`(1+tan^2A)/(1+cot^2A) = (1+(sin^2A)/cos^2A)/(1+(cos^2A)/(sin^2A))`
= `((cos^2A + sin^2A)/cos^2A)/((sin^2A + cos^2A)/sin^2A)`
= `(1/cos^2A)/(1/sin^2A)`
= `(sin^2A)/cos^2A`
= `tan^2A`
Hence, alternative tan2 A is correct.
APPEARS IN
संबंधित प्रश्न
Prove that ` \frac{\sin \theta -\cos \theta +1}{\sin\theta +\cos \theta -1}=\frac{1}{\sec \theta -\tan \theta }` using the identity sec2 θ = 1 + tan2 θ.
Prove the following trigonometric identities.
`tan^2 theta - sin^2 theta tan^2 theta sin^2 theta`
Prove the following trigonometric identities.
if `T_n = sin^n theta + cos^n theta`, prove that `(T_3 - T_5)/T_1 = (T_5 - T_7)/T_3`
If a cos θ + b sin θ = m and a sin θ – b cos θ = n, prove that a2 + b2 = m2 + n2
Prove the following identities:
`sinA/(1 + cosA) = cosec A - cot A`
If m = a sec A + b tan A and n = a tan A + b sec A, then prove that : m2 – n2 = a2 – b2
If `( cos theta + sin theta) = sqrt(2) sin theta , " prove that " ( sin theta - cos theta ) = sqrt(2) cos theta`
Write the value of `(1 + cot^2 theta ) sin^2 theta`.
If `sqrt(3) sin theta = cos theta and theta ` is an acute angle, find the value of θ .

From the figure find the value of sinθ.
If tanθ `= 3/4` then find the value of secθ.
Prove the following identity :
`(cos^3θ + sin^3θ)/(cosθ + sinθ) + (cos^3θ - sin^3θ)/(cosθ - sinθ) = 2`
Without using trigonometric identity , show that :
`sec70^circ sin20^circ - cos20^circ cosec70^circ = 0`
Prove that: sin4 θ + cos4θ = 1 - 2sin2θ cos2 θ.
Prove that: `(1 + cot^2 θ/(1 + cosec θ)) = cosec θ`.
Prove that : `tan"A"/(1 - cot"A") + cot"A"/(1 - tan"A") = sec"A".cosec"A" + 1`.
Choose the correct alternative:
tan (90 – θ) = ?
Prove that sin θ (1 – tan θ) – cos θ (1 – cot θ) = cosec θ – sec θ
Given that sinθ + 2cosθ = 1, then prove that 2sinθ – cosθ = 2.
