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प्रश्न
`(1 + cot^2A)/(1 + tan^2A)` = ?
पर्याय
tan2A
sec2A
cosec2A
cot2A
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उत्तर
cot2A
Explanation:
`(1 + cot^2A)/(1 + tan^2A)`
= `("cosec"^2A)/(sec^2A)`
= `(1/(sin^2A))/(1/(cos^2A))`
= `(cos^2A)/(sin^2A)`
= cot2A
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संबंधित प्रश्न
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Activity:
L.H.S = `square`
= `square (1 - (sin^2theta)/(tan^2theta))`
= `tan^2theta (1 - square/((sin^2theta)/(cos^2theta)))`
= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/square)`
= `tan^2theta (1 - square)`
= `tan^2theta xx square` .....[1 – cos2θ = sin2θ]
= R.H.S
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