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If cos θ = 24/25, then sin θ = ?

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प्रश्न

If `cos θ = 24/25`, then sin θ = ?

योग
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उत्तर

`cos θ = 24/25`   ...[Given]

We know that,

sin2θ + cos2θ = 1

∴ `sin^2θ + (24/25)^2 = 1`

∴ `sin^2θ + 576/625 = 1`

∴ `sin^2θ = 1 - 576/625`

∴ `sin^2θ = (625 - 576)/625`

∴ `sin^2θ = 49/625`

∴ `sin θ = 7/25`   ...[Taking square root of both sides]

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अध्याय 6: Trigonometry - Exercise

संबंधित प्रश्न

If secθ + tanθ = p, show that `(p^{2}-1)/(p^{2}+1)=\sin \theta`


(1 + tan θ + sec θ) (1 + cot θ − cosec θ) = ______.


Prove the following trigonometric identities

`(1 + tan^2 theta)/(1 + cot^2 theta) = ((1 - tan theta)/(1 - cot theta))^2 = tan^2 theta`


Prove the following identities:

`cosA/(1 - sinA) = sec A + tan A`


Prove that:

`(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB) = 0`


Prove the following identities:

`cot^2A((secA - 1)/(1 + sinA)) + sec^2A((sinA - 1)/(1 + secA)) = 0`


If sec A + tan A = p, show that:

`sin A = (p^2 - 1)/(p^2 + 1)`


`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

 


Write the value of `cosec^2 theta (1+ cos theta ) (1- cos theta).`


Write the value of`(tan^2 theta  - sec^2 theta)/(cot^2 theta - cosec^2 theta)`


Find the value of `(cos 38° cosec 52°)/(tan 18° tan 35° tan 60° tan 72° tan 55°)`


Write the value of cosec2 (90° − θ) − tan2 θ. 


If \[\sin \theta = \frac{1}{3}\] then find the value of 9tan2 θ + 9. 


Prove the following identity : 

`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (cosA + 1)/sinA`


Prove the following identity : 

`sqrt((secq - 1)/(secq + 1)) + sqrt((secq + 1)/(secq - 1))` = 2 cosesq


Prove that `(sin (90° - θ))/cos θ + (tan (90° - θ))/cot θ + (cosec (90° - θ))/sec θ = 3`.


If tan A + sin A = m and tan A − sin A = n, then show that `m^2 - n^2 = 4 sqrt (mn)`.


If sinθ – cosθ = 0, then the value of (sin4θ + cos4θ) is ______.


Show that, cotθ + tanθ = cosecθ × secθ

Solution :

L.H.S. = cotθ + tanθ

= `cosθ/sinθ + sinθ/cosθ`

= `(square + square)/(sinθ xx cosθ)`

= `1/(sinθ xx cosθ)` ............... `square`

= `1/sinθ xx 1/square`

= cosecθ × secθ

L.H.S. = R.H.S

∴ cotθ + tanθ = cosecθ × secθ


(1 – cos2 A) is equal to ______.


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