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प्रश्न
If `cos θ = 24/25`, then sin θ = ?
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उत्तर
`cos θ = 24/25` ...[Given]
We know that,
sin2θ + cos2θ = 1
∴ `sin^2θ + (24/25)^2 = 1`
∴ `sin^2θ + 576/625 = 1`
∴ `sin^2θ = 1 - 576/625`
∴ `sin^2θ = (625 - 576)/625`
∴ `sin^2θ = 49/625`
∴ `sin θ = 7/25` ...[Taking square root of both sides]
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Solution:
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∴ 1 + tan2 θ = `(25/7)^square`
∴ tan2 θ = `625/49 - square`
= `(625 - 49)/49`
= `square/49`
∴ tan θ = `square/7` ........(by taking square roots)
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