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प्रश्न
Write the value of`(tan^2 theta - sec^2 theta)/(cot^2 theta - cosec^2 theta)`
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उत्तर
`(tan^2 theta - sec^2 theta )/ (cot^2 theta - cosec^2 theta)`
=` (-1)/(-1)`
= 1
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We have, 1 + cot2θ = cosec2θ
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`square/square` = cosec2θ ......[Taking root on the both side]
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and sin θ = `1/("cosec" θ)`
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∴ sin θ = `9/41`
The value is cosec θ = `41/9`, and sin θ = `9/41`
Eliminate θ if x = r cosθ and y = r sinθ.
