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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

(1 – tan^2 45^circ)/(1 + tan^2 45^circ) = ?

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प्रश्न

`(1 - tan^2 45^circ)/(1 + tan^2 45^circ)` = ?

बेरीज
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उत्तर

`(1 - tan^2 45^circ)/(1 + tan^2 45^circ)`

= `(1 - (1)^2)/(1 + (1)^2)`   ...[∵ tan 45° = 1]

= `(1 - 1)/(1 + 1)`

= `0/2`

= 0

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पाठ 6: Trigonometry - Exercise

संबंधित प्रश्‍न

Prove the following identities:

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`(iii) sec^4 θ– sec^2 θ = tan^4 θ + tan^2 θ`


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Prove the following identities:

`(cot^2 theta (sec theta - 1))/((1 + sin theta)) + (sec^2 theta(sin theta - 1))/((1 + sec theta)) = 0`


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`[1/((sec^2θ - cos^2θ)) + 1/((cosec^2θ - sin^2θ))](sin^2θcos^2θ) = (1 - sin^2θcos^2θ)/(2 + sin^2θcos^2θ)`


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