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प्रश्न
`(1 - tan^2 45^circ)/(1 + tan^2 45^circ)` = ?
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उत्तर
`(1 - tan^2 45^circ)/(1 + tan^2 45^circ) = (1 - (1)^2)/(1 + (1)^2)` ...[∵ tan 45° = 1]
= `(1 - 1)/(1 + 1)`
= `0/2`
= 0
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Solution :
L.H.S. = cotθ + tanθ
= `cosθ/sinθ + sinθ/cosθ`
= `(square + square)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ............... `square`
= `1/sinθ xx 1/square`
= cosecθ × secθ
L.H.S. = R.H.S
∴ cotθ + tanθ = cosecθ × secθ
